A. s = 120
B. s = 40
C. s = 30
D. s = 9
I'm thinking B/40 ??? Any opinions. I'm trying so hard to understand this algebra stuff, never took it in high school many of years ago, and now going back to school to get my diploma. any help is so much appreciated.
13 Answers

2s + s + 12 =132
3s +12 =132
3s = 120
s = 40

This is a simple question
2s+s+12=132
From (A.) substitute the value of s
2(120) + 120+ 12
2* 120+120+12 will not be equal to 132
similarly,
in option B,
2(40) + 40+ 12 = 132
2*40 +40+12=132
132 = 132
LHS = RHS
Hence proved
Similarly try for all other options!
If LHS = RHS,
Then the equation is correct
Good Day

Yes, S = 40.
Here is how to get it.
2S + S + 12 = 132
2S + S = 132  12
3S = 120
S = 120 / 3
S = 40
Intro to Algebra is easy as long as you know your multiplication Table and remember to change the sign when you move numbers or sign to the other side of the equal sign.
Good luck on your diploma. =)

2s+s+12=132 First you combine like terms
3s+12=132 Then you subtract 12 from both sides
3s=120 Then you divide by 3 on both sides
s=40

Think of the single "s" as being "1s". So,
2s + 1s + 12 = 132
Get the 12 on the other side of the equals sign by subtracting (since 12 is positive on the one side, you would just reverse signs to get it on the other side. If it were negative, then you would add 12). Anything you do on one side of the equals sign you will do on the other side:
2s + 1s + 12  12 = 132  12
2s + 1s = 120
Then, you can add the s values:
2s + 1s = 120
3s = 120
Now you solve for s. Since 3s is really 3 times s (3 X s), you would divide by 3 to get the value of just s. Again, what you do on one side of the equals sign you do on the other:
3s/3 = 120/3
s = 40
Hope this helps.

12  132 = 120. 3s=120 divide S= 40

2s + s + 12 = 132
3s + 12 = 132
3s = 132  12
3s = 120
s = 120/ 3
s = 40
so it is B

2s + s+ 12 =132
3s +12 = 132
3s = 132  12
3s = 120
s = 120/3
s = 40
so the answer is b

40

s= 40 because 13212= 120, combine like terms so you get 3s, 3s=120 divide by 3 and your answer is 40.